Replies

1. 
   Guest_ | May 03, 2000 12:17am | #1

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   Give 'em Hell Andrew! Joe H

   PS. Look in the archives, this subject has been hashed & rehashed. The absolute easiest & best explanation is Andrew D's "Think of the difference between you & your shadow" the crown you need for your rising or falling piece is the equilivant of your shadow....

1. 
   Guest_ | May 03, 2000 12:45am | #2

   *the other way is to turn both corners in your corner...in other words...you have to turn the wall angle and with the same piece, turn the cathedral angle...a piece that looks like a slice of pie will get you to your piece that goes up the cathedral...got it?near the stream,aj

1. 
   Guest_ | May 03, 2000 02:34am | #3

   *Good point.JLC (I thought JLC) had a write up and diagrams about six months back showing how to detail the turn as you described. It's different, but it works.

1. 
   Guest_ | May 03, 2000 04:25am | #4

   *Couldn't you just divide the obtuse angel by half for your miter and then cut it ten or so times til you get it right, (that's me)

2. 
   Adam_Greisz | May 08, 2000 06:12am | #5

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   Since the profiles do not match when you cut outside miters on diferrent angles (i.e. one parallel and one at 10 degrees) you need to get both pieces running at the same angle. The easiest way to do this is to use a pie shaped piece to change the angle of the piece running at 10 degrees to make it run parallel with the floor. It is then simple to run a ordinary outside corner.

3. 
   Guest_ | May 08, 2000 02:53pm | #6

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   Adam...and I are both recommending the pie...apple pie, right Adam?..

   near the stream,

   aj

4. 
   Adam_Greisz | May 09, 2000 06:46am | #7

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   You are correct Jack, Apple pie of course!

5. 
   Tim_Colburn | May 09, 2000 06:46am | #8

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   Anyone have tips to figure out the angles (bevel and mitre) required
   to install crown for an outside corner (90 degree) where the left outside
   piece of crown is typical (running parallel to the floor) and the right
   outside piece of crown is falling off at 10 degrees? Will the same
   calculations work for inside corne